(x+5)(x^2-7x+12)=0

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Solution for (x+5)(x^2-7x+12)=0 equation:


Simplifying
(x + 5)(x2 + -7x + 12) = 0

Reorder the terms:
(5 + x)(x2 + -7x + 12) = 0

Reorder the terms:
(5 + x)(12 + -7x + x2) = 0

Multiply (5 + x) * (12 + -7x + x2)
(5(12 + -7x + x2) + x(12 + -7x + x2)) = 0
((12 * 5 + -7x * 5 + x2 * 5) + x(12 + -7x + x2)) = 0
((60 + -35x + 5x2) + x(12 + -7x + x2)) = 0
(60 + -35x + 5x2 + (12 * x + -7x * x + x2 * x)) = 0
(60 + -35x + 5x2 + (12x + -7x2 + x3)) = 0

Reorder the terms:
(60 + -35x + 12x + 5x2 + -7x2 + x3) = 0

Combine like terms: -35x + 12x = -23x
(60 + -23x + 5x2 + -7x2 + x3) = 0

Combine like terms: 5x2 + -7x2 = -2x2
(60 + -23x + -2x2 + x3) = 0

Solving
60 + -23x + -2x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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